## Solving Quadratic Problems Involving Brackets

### Algebra: Solve for x Help

#### Home | Solve for x menu | Algebra menu

Suppose you have a problem like:

(2x-5)(3x-2) = (-4x-3)(x+2)

All you do is use FOIL to get rid of the brackets. In our example we get:

(2x-5)(3x-2) = (-4x-3)(x+2)

6x^{2}-19x+10 = -4x^{2}-11x-6

We can then proceed with our basic strategy.

**AN EXCEPTION TO USING FOIL**. Check to
see if there is a common term on either side of the equation. If there
is, you can divide by that term (the caveat is that it is not equal to
zero).

**Example:**

(2x-5)(3x-2) = (-4x-3)(3x-2)

Assuming that x = 2/3 is not a solution, we can divide both sides of the equation by (3x-2).(2x-5)(3x-2) = (-4x-3)(3x-2)

2x-5 = -4x-3

This makes your life a bit easier.

## Algebra: Solve for x Help

### What do you need help with? Click on one of the following topics...

Basic multiply/divide solve for x

Basic add/multiply mixtures

Solving basic problems involving brackets

What is cross-multiplying?

What is the quadratic formula?

Strategy for solving quadratic problems

Solving quadratic problems involving brackets

Solving quadratic problems involving fractions

Copyright © 2011 - Mathwizz.com all rights reserved