Solving Quadratic Problems Involving Brackets
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Suppose you have a problem like:
(2x-5)(3x-2) = (-4x-3)(x+2)
All you do is use FOIL to get rid of the brackets. In our example we get:
(2x-5)(3x-2) = (-4x-3)(x+2)
6x2-19x+10 = -4x2-11x-6
We can then proceed with our basic strategy.
AN EXCEPTION TO USING FOIL. Check to see if there is a common term on either side of the equation. If there is, you can divide by that term (the caveat is that it is not equal to zero).
Example:
(2x-5)(3x-2) = (-4x-3)(3x-2)
Assuming that x = 2/3 is not a solution, we can divide both sides of the equation by (3x-2).(2x-5)(3x-2) = (-4x-3)(3x-2)
2x-5 = -4x-3
This makes your life a bit easier.

Algebra: Solve for x Help
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