STAT177 Homework sheet #4 Solutions
1) Ho: m ³ 20000
Ha: m < 20000
2) The appropriate test is the Z test. Here are the output results:
|
Z test
for one mean |
|
Ho:
population mean is not less than 20000 |
|
Ha:
population mean is less than 20000 |
|
Reject Ho
if test statistic < -1.645 |
|
Test
statistic = -1.405 |
|
P-value =
0.08 |
|
Do not
reject Ho |
|
Conclude
population mean is not less than 20000 |
|
95%
confidence interval: 15710.914 to 20707.086 |
Since the p-value is greater than the level of significance, we do not reject the null hypothesis. We conclude that average daily sales are not significantly less than $20,000.
3) Since we did not reject the null hypothesis, we could have committed a Type II error.
4) We would have rejected the null hypothesis if the level of significance were between 8% and 10%, since the p-value would then be less than the level of significance.
5) Ho: m £ 780000
Ha: m > 780000
6) Since the scale of the data is interval/ratio, the data is normally distributed, the population standard deviation is unknown, the appropriate test is the t test.
7) It is fine to leave the level of significance in the dialogue box at 5%; we’ll be using the general rule of thumb. Here is the output:
|
t test
for one mean |
|
Ho:
population mean is not greater than 780000 |
|
Ha:
population mean is greater than 780000 |
|
Reject Ho
if test statistic > 1.895 |
|
Test
statistic = 0.132 |
|
P-value =
0.449 |
|
Do not
reject Ho |
|
Conclude
population mean is not greater than 780000 |
|
95%
confidence interval: 648070.69 to 927550.56 |
Since the p-value is greater than 10%, under the general rule of thumb, we do not reject the null hypothesis. We conclude the training was not successful.
8) The answer is no since the p-value is greater than 10% under the general rule of thumb.
9) Ho: m £ 120
Ha: m > 120
10) Since the scale of the data is interval/ratio, the data is normally distributed, the population standard deviation is unknown, the appropriate test is the t test.
11) Here is the output:
|
t test
for one mean |
|
Ho:
population mean is not greater than 120 |
|
Ha:
population mean is greater than 120 |
|
Reject Ho
if test statistic > 1.796 |
|
Test
statistic = 6.125 |
|
P-value =
0 |
|
Reject Ho |
|
Conclude
population mean is greater than 120 |
|
95%
confidence interval: 143.385 to 169.615 |
Since the p-value is zero, we would reject the null hypothesis regardless of the level of significance. We conclude the store should locate in Smallville.
12) The p-value is less than 1%. We would still reject the null hypothesis and reach the same conclusion.
13) Since the scale of the data is ordinal, the appropriate test is the Wilcoxon test.
14) Here is the output:
|
Wilcoxon
test for one median |
|
Ho:
population median is not greater than 7 |
|
Ha:
population median is greater than 7 |
|
Reject Ho
if test statistic less than or equal to 6 |
|
Sample
size = 8 |
|
Test
statistic = 8.5 |
|
Do not
reject Ho |
|
Conclude
population median is not greater than 7 |
Since the test statistic is greater than 6, we do not reject the null hypothesis. We conclude they should not proceed with this peanut butter.
15) The first thing to do is copy the values in A1 through A10 to A11 through A20. Here is the output:
|
Wilcoxon
test for one median |
|
Ho:
population median is not greater than 7 |
|
Ha:
population median is greater than 7 |
|
Reject Ho
if test statistic less than or equal to 36 |
|
Sample
size = 16 |
|
Test
statistic = 32 |
|
Reject Ho |
|
Conclude
population median is greater than 7 |
This time, since the test statistic is less than 36, we reject the null hypothesis and conclude they should proceed with this peanut butter.