## Solving Radical Inequality Problems

### Algebra: Inequalities Help

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I'll be honest. These are among the hardest algebra problems you'll ever have to solve in high school. There is a scene in the movie "Lawrence of Arabia" where they're crossing the desert. What they had to do is just slightly more difficult than solving these types of problems. The hardest part is keeping the logic straight. If you do that, you win the game. Rather than bore you with a bunch of theory, let's get right into the examples and I'll explain the logic as we go along.

By the way, you should know how to expand FOIL expressions, and use the quadratic formula to solve for the roots of the equation.

**Example 1:** Solve:

There are 2 logic hurdles we have to jump. The first is that **you
can't have the square root of a negative number.** That means
3x - 2 __>__ 0 or
x __>__ 2/3.

The second logic hurdle is this: since the left hand side is greater
than or equal to zero and it is less than the right hand side, that means
**the right hand side must be greater than zero,** which
means 2x - 3 > 0 or
x > 3/2. Combining these two conditions
together, we must satisfy the condition of
x > 3/2, which is the same as
x > 1.5 converting the fraction to a
decimal number. If we didn't take this into
consideration before squaring both sides, we would end up with all sorts
of problems.

The next step is to square both sides and bring everything over to one side.

3x - 2 < (2x - 3)^{2}

3x - 2 < 4x^{2} - 12x + 9

4x^{2} - 15x + 11 > 0

And now for the next logic hurdle. Since this is a parabola, we need
the parts of the parabola where **y > 0**. The first step is to
solve for the roots of the equation using the
quadratic formula. In this case, the roots are
1 and 2.75
This is made clear looking at the graph of the equation
^{2} - 15x + 11.

The parts of the parabola where y > 0 are x < 1 and x > 2.75.

But, if you recall from the beginning of the problem, we have the condition of x > 1.5. That eliminates the solution of x < 1. So the solution to our problem is x > 2.75.

The next example illustrates the point that keeping the logic straight not only helps you get the right answer but makes your life easier to boot.

**Example 2:** Solve:

Because the left hand side is greater than the right hand side, we have two cases to consider: 1) the right hand side is less than zero and 2) the right hand side is greater than zero.

As before, since we can't have the square root of a negative number,
we have the condition __>__ 0__>__ 2.5

Let's take the first case where the right hand side is less than
zero. We do this one first because if the right hand side is less than zero,
the left hand side is automatically greater since it is greater than or equal to zero.
We have -4x + 3 < 0 or
x > 0.75. Since we must satisfy the
condition of x __>__ 2.5 our solution is
x __>__ 2.5. Notice that we didn't have to
square both sides to find the solution for this case. Isn't that
nice?

For the second case where the right hand side is greater than zero,
we have **WE CAN'T HAVE x < 0.75 AND x > 2.5 AT THE SAME TIME.** Ergo,
there is no solution for the second case.
The only solution for this problem is from the first case.

By the way, if we had gone ahead and blindly squared both sides, we
would have ended up with
^{2} - 26x + 14 < 0.

## Algebra: Inequalities Help

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