Suppose you have a problem like:
The first thing you do is find out what the solution can't be so that
you don't end up dividing by zero. In this
example, that means neither (3x-2) nor (x+2) can be
zero. So, x cannot be either 2/3 or -2 for a solution.
Once you've taken care of that, you
to get (2x-5)(x+2) = (-4x-3)(3x-2) and proceed with the
strategy for solving quadratics